# Calculate the mass of 5 liters of a mixture of 10% ozone and 90% nitrogen.

1) Calculate the mass of 5 liters of nitrogen:

a) the mass of 22.4 liters of N2 is equal to the molecular mass of nitrogen gas = 14 * 2 = 28 (g).

b) Calculate the mass of 5 liters of nitrogen:

28 g of nitrogen take up a volume of 22.4 liters,
This means that x grams of nitrogen takes up a volume of 5 liters.

x = 28 * 5: 22.4 = 6.25 (g).

2) Let’s find what weight 90% of nitrogen has, in its five liters:

6.25 g – 100%

x g – 90%.

x = 6.25 * 90: 100 = 5.62 (g).

3) According to the same scheme as in points 1) – 2) of this solution of the problem, we find the mass of 10% ozone.

Please note that the formula for ozone is O3, which means its molecular weight is 16 * 3 = 48.

48 g – 22.4 L

x g – 5 l;

x = 48 * 5: 22.4 = 10.71 (g) – the mass of 5 liters of ozone.

10.71 g – 100%

x g – 10%;

x = 10.71 * 10: 100 = 1.07 (g) is the mass of ten percent of 5 liters of ozone.

4) Now it remains to add the mass of 10% ozone and the mass of 90% nitrogen:

1.07 + 5.62 = 6.7 (d). This is the total mass of 5 liters of the mixture.

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