Calculate the mass of a 10 percent sulfuric acid solution that will be required to completely neutralize 50 grams of sodium hydroxide.
H2SO4 + 2NaOH = Na2SO4 + H2O
We find the chemical amount by the formula: n = m / M
n (NaOH) = 50 / (23 + 16 + 1) = 50/40 = 1.25 mol.
We write out the chemical quantities and coefficients of the substances H2SO4 – NaOH, respectively:
x mol – 1.25 mol, therefore n (H2SO4) = x = 1 * 1.25 / 2 = 0.625 mol
1 mol – 2 mol
m (in-va) (H2SO4) = 0.625 * (2 * 1 + 32 + 16 * 4) = 0.625 * 98 = 61.25 gr.
Mass of hydrochloric acid solution:
w = m (in-va) / m (pa-pa), therefore m (pa-pa) = m (in-va) / w, where w is substituted Not as a percentage, that is, w = 10% / 100% = 0.1.
m (pa-pa) (H2SO4) = 61.25 / 0.1 = 612.5 gr.
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