Calculate the mass of a 25% nitric acid solution, which is required to completely

Calculate the mass of a 25% nitric acid solution, which is required to completely neutralize 18.5 g of calcium hydroxide.

Calcium hydroxide enters into a neutralization reaction with nitric acid. The result is water and calcium nitrate salt.

2 HNO3 + Ca (OH) 2 = 2 H2O + Ca (NO3) 2

Molar masses of substances:

M (HNO3) = 63 g / mol; M (Ca (OH) 2) = 74 g / mol.

Let’s make a proportion according to the reaction equation and calculate the mass of nitric acid:

X g HNO3 corresponds to 18.5 g Ca (OH) 2, as

2 * 63 g / mol HNO3 corresponds to 74 g / mol Ca (OH) 2.

X = (18.5 * 2 * 63) / 74 = 31.5 g of nitric acid.

Now we need to calculate the mass of a nitric acid solution with a mass fraction of 25%.

m (solution) = (31.5 * 100) / 25 = 126 g of nitric acid solution.

Answer: the mass of the nitric acid solution is 126 g.



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