# Calculate the mass of aluminum hydroxide that is formed by the interaction of aluminum

Calculate the mass of aluminum hydroxide that is formed by the interaction of aluminum sulfate with slaked lime weighing 7.4 g.

The equation for the reaction of calcium hydroxide (slaked lime) with aluminum sulfate:

3Ca (OH) 2 + Al2 (SO4) 3 = 2Al (OH) 3 + 3CaSO4

Amount of calcium hydroxide substance:

v (Ca (OH) 2) = m (Ca (OH) 2) / M (Ca (OH) 2) = 7.4 / 74 = 0.1 (mol).

According to the reaction equation, for 3 mol of Ca (OH) 2 2 mol of Al (OH) 3 are formed, therefore:

v (Al (OH) 3) = v (Ca (OH) 2) * 2/3 = 0.1 * 2/3 = 2/30 = 1/15 (mol).

Thus, the mass of the formed aluminum hydroxide is:

m (Al (OH) 3) = v (Al (OH) 3) * M (Al (OH) 3) = (1/15) * 78 = 5.2 (g). One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.