Aluminum enters into an active reaction with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.
Al + 3HCl = AlCl3 + 3/2 H2;
N H2 = 1.5 mol;
To obtain such an amount of hydrogen, it is required to dissolve 1.5 x 2/3 = 1 mol of aluminum.
Let’s determine its weight.
M Al = 27 grams / mol;
m Al = 27 x 1 = 27 grams;
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