m (Ba) = 27.4 g
m (BaO) -?
2Ba + O2 = 2BaO, – we solve the problem using the composed reaction equation:
1) Find the amount of barium contained in 27.4 grams of the substance:
n (Ba) = m: M = 27.4 g: 137 g / mol = 0.2 mol.
2) We compose a logical expression:
if 2 mol of Ba gives 2 mol of BaO,
then 0.2 mol of Ba will give x mol of BaO,
then x = 0.2 mol.
3) Find the mass of barium oxide formed during the reaction:
m (BaO) = n * M = 0.2 mol * 153 g / mol = 30.6 g.
Answer: m (BaO) = 30.6 g.
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