Calculate the mass of barium oxide that is formed by the interaction of 27.4 g of barium with oxygen.


m (Ba) = 27.4 g

To find:

m (BaO) -?


2Ba + O2 = 2BaO, – we solve the problem using the composed reaction equation:

1) Find the amount of barium contained in 27.4 grams of the substance:

n (Ba) = m: M = 27.4 g: 137 g / mol = 0.2 mol.

2) We compose a logical expression:

if 2 mol of Ba gives 2 mol of BaO,

then 0.2 mol of Ba will give x mol of BaO,

then x = 0.2 mol.

3) Find the mass of barium oxide formed during the reaction:

m (BaO) = n * M = 0.2 mol * 153 g / mol = 30.6 g.

Answer: m (BaO) = 30.6 g.

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