Let’s compose the reaction equation for the decomposition of calcium carbonate:
CaCO3 = CaO + CO2;
The relative atomic mass of calcium is 40 g / mol; carbon is equal to 12 g / mol; oxygen is 16 g / mol. Find the molecular weight of calcium carbonate:
40 + 12 + 16 * 3 = 100 g / mol;
Let’s find the amount of substance in calcium carbonate:
70/100 = 0.7 mol:
The amount of substance in calcium oxide is 0.7 mol, since there are the same coefficients in front of CaO and in front of CaCO3. The molecular weight of calcium oxide is 56 g / mol. Find the mass of calcium oxide:
56 * 0.7 = 39.2 grams;
Answer: The mass of calcium oxide is 39.2 grams.
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