# Calculate the mass of copper formed during the reduction of copper oxide (2)

Calculate the mass of copper formed during the reduction of copper oxide (2) by hydrogen with a mass of 60 g with a mass fraction of impurities of 10%.

The reaction of copper reduction with hydrogen is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

1 mol of gas is reacted with 1 mol of copper oxide. 1 mole of copper is synthesized.

Let’s calculate the available chemical amount of copper oxide substance.

M СuO = 64 + 16 = 80 grams / mol;

N CuO = 60 x 0.9 / 80 = 0.675 mol;

For this reaction 0.675 mol of copper is synthesized.

Let’s calculate its weight.

M Сu = 64 grams / mol;

m Cu = 0.675 x 64 = 43.2 grams;

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