Calculate the mass of copper (II) hydroxide, which is formed by the interaction of 200 g of 20% sodium hydroxide solution and an excess of copper (II) sulfate solution. The reaction also produces sodium sulfate.
m (solution) = 200 g
w (NaOH) = 20%
1) Calculate the mass of the solute, because it is it that enters into the reaction:
m (NaOH) = m solution (NaOH) * w (NaOH)
m (NaOH) = 200 * 20/100 = 40g
2) Make the equation of the chemical reaction:
2 NaOH + CuSO4 = Na2SO4 + Cu (OH) 2
3) calculate the amount of sodium hydroxide substance
n (NaOH) = 40/40 = 1 mol
4) Calculate the amount of copper (II) hydroxide substance
n (Cu (OH) 2) = 1/2 = 0.5 mol
5) Determine the mass of copper (II) hydroxide substance
m (Cu (OH) 2) = 0.5 * 98 = 48 g.
Answer: 48 g.
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