# Calculate the mass of copper oxide formed during the decomposition of 98 g of copper hydroxide.

September 15, 2021 | education

| Let’s write down the solution, compose an equation according to the condition of the problem:

Cu (OH) 2 = CuO + H2O – the decomposition reaction of copper hydroxide occurs when heated, copper oxide is formed;

Let’s make calculations using the formulas:

MCu (OH) 2 = 97.5 g / mol;

M (CuO) = 79.5 g / mol.

Determine the amount of mol of copper hydroxide, if the mass is known:

YCu (OH) 2 = m / M = 98 / 97.5 = 1.005 mol;

According to the equation, the amount of moles of copper hydroxide and copper oxide is equal to 1 mole, which means that Y (CuO) = 1.005 mole.

Find the mass of copper oxide:

m (CuO) = Y * M = 1.005 * 79.5 = 79.89 g.

Answer: the mass of copper oxide is 79.89 g.

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