# Calculate the mass of copper oxide required to obtain 320 g of copper sulfate.

Let’s implement the solution:
1. Let’s write down the reaction equation:
CuO + H2SO4 = CuSO4 + H2O – ion exchange reaction, copper sulfate was obtained;
2. Let’s make the calculations:
M (CuO) = 63.5 + 16 = 79.5 g / mol;
M (CuSO4) = 63.5 + 32 + 64 = 159.5 g / mol;
3. Determine the number of mol of CuSO4, if the mass is known:
Y (CuSO4) = m (CuSO4) / M (CuSO4) = 320 / 159.5 = 2 mol;
4. Let’s make a proportion according to the reaction equation:
X mol (CuO) – 2 mol (CuSO4);
-1 mol -1 mol hence, X mol (CuO) = 2 * 1/1 = 2 mol;
5. Let’s calculate the mass of copper oxide:
M (CuO) = Y (CuO) * M (CuO) = 2 * 79.5 = 159 g.
Answer: the reaction requires copper oxide weighing 159 g.

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