Calculate the mass of hydrogen that is released by the interaction of 12 grams of Mg with sulfuric acid.

univerkov | December 30, 2020 | education

Calculate the mass of hydrogen that is released by the interaction of 12 grams of Mg with sulfuric acid
H2so4 + Mg = MgSo4 + H2
n (mg) = m / M = 12/24 = 0.5
n (H2) = n (Mg) = 0.5 mol
m (Mg) = n * M = 0.5 * 1 = 0.5 g

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