Calculate the mass of iron hydroxide lll obtained as a result of the reaction of iron chloride
Calculate the mass of iron hydroxide lll obtained as a result of the reaction of iron chloride lll with magnesium hydroxide m = 20g
1. Ferric hydroxide is obtained according to the equation:
2FeCl3 + 3Mg (OH) 2 = 2Fe (OH) 3 + 3MgCl2;
2. Knowing the mass of magnesium hydroxide, we find its chemical amount:
n (Mg (OH) 2) = m (Mg (OH) 2): M (Mg (OH) 2);
M (Mg (OH) 2) = 24 + 2 * 17 = 58 g / mol;
n (Mg (OH) 2) = 20: 58 = 0.3448 mol;
3. The amounts of the obtained iron hydroxide and the initial magnesium hydroxide are related as 2: 3, we determine the amount of Fe (OH) 3:
n (Fe (OH) 3) = n (Mg (OH) 2) * 2: 3 = 0.3448 * 2: 3 = 0.23 mol;
4. Let’s calculate the mass of iron hydroxide (3):
m (Fe (OH) 3) = n (Fe (OH) 3) * M (Fe (OH) 3);
M (Fe (OH) 3) = 56 + 3 * 17 = 107 g / mol;
m (Fe (OH) 3) = 0.23 * 107 = 24.61 g.
Answer: 24.61 g.
