Calculate the mass of iron hydroxide lll obtained as a result of the reaction of iron chloride

Calculate the mass of iron hydroxide lll obtained as a result of the reaction of iron chloride lll with magnesium hydroxide m = 20g

1. Ferric hydroxide is obtained according to the equation:

2FeCl3 + 3Mg (OH) 2 = 2Fe (OH) 3 + 3MgCl2;

2. Knowing the mass of magnesium hydroxide, we find its chemical amount:

n (Mg (OH) 2) = m (Mg (OH) 2): M (Mg (OH) 2);

M (Mg (OH) 2) = 24 + 2 * 17 = 58 g / mol;

n (Mg (OH) 2) = 20: 58 = 0.3448 mol;

3. The amounts of the obtained iron hydroxide and the initial magnesium hydroxide are related as 2: 3, we determine the amount of Fe (OH) 3:

n (Fe (OH) 3) = n (Mg (OH) 2) * 2: 3 = 0.3448 * 2: 3 = 0.23 mol;

4. Let’s calculate the mass of iron hydroxide (3):

m (Fe (OH) 3) = n (Fe (OH) 3) * M (Fe (OH) 3);

M (Fe (OH) 3) = 56 + 3 * 17 = 107 g / mol;

m (Fe (OH) 3) = 0.23 * 107 = 24.61 g.

Answer: 24.61 g.



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