Calculate the mass of iron that can be obtained from 325 kg. Magnetic iron ore mass of impurities is 15%

| July 29, 2021 | education

Calculate the mass of iron that can be obtained from 325 kg. Magnetic iron ore mass of impurities is 15%. CO was used as a reducing agent.

Let’s implement the solution:
1. We write down the equation according to the problem statement:
m = 325 kg; 15% impurity;
Fe3O4 + 4CO = 3Fe + 4CO2 – OBP, iron obtained;
X g -?
2. Let’s calculate the molar mass of substances:
M (Fe3O4) = 231.4 g / mol;
M (Fe) = 55.8 g / mol.
3. Determine the mass of ore without impurities, as well as the amount:
m (Fe3O4) = 326000 (1 – 0.15) = 276250 g;
Y (Fe3O4) = m / M = 276250 / 231.4 = 1193.8 mol.
4. Proportion:
1193.8 mol (Fe3O4) – X mol (Fe);
-1 mol -3 mol from here, X mol (Fe) = 1193 * 3/1 = 3581.5 mol.
5. Find the mass of the product:
m (Fe) = Y * M = 3581.5 * 55.8 = 199847.7 g. = 199 kg. 848 BC
Answer: received iron weighing 199 kg. 848 BC



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