Calculate the mass of oxygen required for complete combustion of 67.2 liters of propane.

The propane oxidation reaction is described by the following chemical reaction equation.

C3H8 + 5O2 = 3CO2 + 4H2O;

According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.

Let’s calculate the amount of propane available.

To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.

N C3H8 = 67.2 / 22.4 = 3 mol;

The amount of oxygen will be.

N O2 = 3 x 5 = 15 mol;

Let’s calculate its weight. To do this, multiply the weight of the substance by the weight of 1 mole.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 15 x 32 = 480 grams;