Calculate the mass of potassium chloride obtained by reacting 80 g of hydrochloric acid with 100 g of potassium hydroxide solution with a mass fraction of 10%.
1. Let’s compose the equality of chemical interaction:
KOH + HCl = KCl + H2O.
2. Calculate the chemical amount of hydrochloric acid and potassium hydroxide:
n (HCl) = m (HCl) / M (HCl) = 80 g / 36.5 g / mol = 2.19 mol.
m (KOH) = m (solution) * ω (KOH) / 100% = 100 g * 10% / 100% = 10 g.
n (KOH) = m (KOH) / M (KOH) = 10 g / 56 g / mol = 0.179 mol.
3. Using the equality of chemical interaction, we find the number of moles and, as a result, the mass of potassium chloride:
! KOH is in short supply.
n (KCl) = n (KOH) = 0.179 mol.
m (KCl) = n (KCl) * M (KCl) = 0.179 mol * 75.5 g / mol = 13.5 g.
Result: m (KCl) = 13.5 g.
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