Calculate the mass of sodium phenolate if 0.4 g of sodium hydroxide reacts with an excess of phenol

1. We write down the equation:
С6Н5ОН + NaOH = C6H5O – Na + H2O – ion exchange reaction, sodium phenolate was obtained;
2. Let’s make the calculations:
M (NaOH) = 39.9 g / mol;
M (C6H5ONa) = 122.9 g / mol.
3. Determine the number of moles of the starting material, if the mass is known:
Y (NaOH) = m / M = 0.4 / 39.9 = 0.01 mol;
Y (C6H5ONa) = 1 mol since the amount of substances according to the equation is 1 mol.
4. Find the mass of the product:
m (C6H5ONa) = Y / M = 0.01 * 122.9 = 1.229 g.
Answer: in the course of the reaction, sodium phenolate weighing 1.229 g was obtained.



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