Calculate the mass of sulfur reacted with 12g of magnesium.

1.Let’s find the amount of magnesium substance by the formula: n = m: M.

M (Mg) = 24 g / mol.

n = 12 g: 24 g / mol = 0.5 mol.

2. Let’s compose the equation of the reaction between magnesium and sulfur. Let’s find the quantitative ratios of substances.

Mg + S = MgS.

According to the reaction equation, there is 1 mole of magnesium for 1 mole of sulfur. Therefore, the amount of magnesium and sulfur will be the same.

Then, n (S) = 0.5 mol.

3.Let’s find the mass of sulfur by the formula:

m = n × M,

M ((S) = 32g / mol.

m = 32 g / mol × 0.5 mol = 16 g.

Answer: 16 g.

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