Calculate the mass of sulfur reacted with 12g of magnesium.
September 27, 2021 | education
| 1.Let’s find the amount of magnesium substance by the formula: n = m: M.
M (Mg) = 24 g / mol.
n = 12 g: 24 g / mol = 0.5 mol.
2. Let’s compose the equation of the reaction between magnesium and sulfur. Let’s find the quantitative ratios of substances.
Mg + S = MgS.
According to the reaction equation, there is 1 mole of magnesium for 1 mole of sulfur. Therefore, the amount of magnesium and sulfur will be the same.
Then, n (S) = 0.5 mol.
3.Let’s find the mass of sulfur by the formula:
m = n × M,
M ((S) = 32g / mol.
m = 32 g / mol × 0.5 mol = 16 g.
Answer: 16 g.
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