Calculate the mass of sulfuric acid that reacts with 5.6 g of potassium hydroxide if potassium sulfate and water are formed.
July 25, 2021
m (KOH) = 5.6 g
m (H2SO4) -?
1) H2SO4 + 2KOH => K2SO4 + 2H2O;
2) n (KOH) = m / M = 5.6 / 56 = 0.1 mol;
3) n (H2SO4) = n (KOH) / 2 = 0.1 / 2 = 0.05 mol;
4) m (H2SO4) = n * M = 0.05 * 98 = 4.9 g.
Answer: The mass of H2SO4 is 4.9 g.
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