Calculate the mass of the metal precipitated at the cathode if the electrolysis was carried out at a current strength of A = 2.2

Calculate the mass of the metal precipitated at the cathode if the electrolysis was carried out at a current strength of A = 2.2 for a time of 15 hours. The metal output by current VT was 96%.

Given:
I = 2.2 A
t = 15 h
η (Na) = 96%
F = 26.8 A * h / mol

To find:
m (Na) -?

Decision:
1) 2NaF = (electric current) => 2Na + F2 ↑;
2) m theor. (Na) = M (Na) * I * t / (N (e) * F) = 23 * 2.2 * 15 / (1 * 26.8) = 28.32 g;
3) m practical. (Na) = η (Na) * m theory. (Na) / 100% = 96% * 28.32 / 100% = 27.2 g.

Answer: The mass of Na is 27.2 g.