Calculate the mass of the precipitate that forms when 160 g of 15% copper sulfate (2) interacts
Calculate the mass of the precipitate that forms when 160 g of 15% copper sulfate (2) interacts with an excess of sodium hydroxide. Calculate the amount of substance of the precipitate formed.
1. Let us write down the equation of the proceeding reaction:
CuSO4 + 2NaOH = Cu (OH) 2 ↓ + Na2SO4.
2. Calculate the mass of copper sulfate (2):
m (CuSO4) = w (CuSO4) * m (solution CuSO4) = 0.15 * 160 = 24 g.
3. Find the chemical amount of copper sulfate:
n (CuSO4) = m (CuSO4): M (CuSO4);
M (CuSO4) = 64 + 32 + 4 * 16 = 160 g / mol;
n (CuSO4) = 24: 160 = 0.15 mol.
4. Determine the amount of precipitated copper hydroxide (2):
n (Cu (OH) 2) = n (CuSO4) = 0.15 mol.
5. Let’s calculate the mass of the sediment:
m (Cu (OH) 2) = n (Cu (OH) 2) * M (Cu (OH) 2);
M (Cu (OH) 2) = 64 + 2 * 17 = 98 g / mol;
m (Cu (OH) 2) = 0.15 * 98 = 14.7 g.
Answer: 14.7 g, 0.15 mol.