Calculate the mass of the precipitate that forms when 160 g of 15% copper sulfate (2) interacts

Calculate the mass of the precipitate that forms when 160 g of 15% copper sulfate (2) interacts with an excess of sodium hydroxide. Calculate the amount of substance of the precipitate formed.

1. Let us write down the equation of the proceeding reaction:

CuSO4 + 2NaOH = Cu (OH) 2 ↓ + Na2SO4.

2. Calculate the mass of copper sulfate (2):

m (CuSO4) = w (CuSO4) * m (solution CuSO4) = 0.15 * 160 = 24 g.

3. Find the chemical amount of copper sulfate:

n (CuSO4) = m (CuSO4): M (CuSO4);

M (CuSO4) = 64 + 32 + 4 * 16 = 160 g / mol;

n (CuSO4) = 24: 160 = 0.15 mol.

4. Determine the amount of precipitated copper hydroxide (2):

n (Cu (OH) 2) = n (CuSO4) = 0.15 mol.

5. Let’s calculate the mass of the sediment:

m (Cu (OH) 2) = n (Cu (OH) 2) * M (Cu (OH) 2);

M (Cu (OH) 2) = 64 + 2 * 17 = 98 g / mol;

m (Cu (OH) 2) = 0.15 * 98 = 14.7 g.

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