# Calculate the mass of the precipitate that forms when 160 g of a 15% solution of copper sulfate 2 interacts

**Calculate the mass of the precipitate that forms when 160 g of a 15% solution of copper sulfate 2 interacts with an excess of sodium hydroxide. Additional question. Calculate the amount of sediment-forming substance**

Find the mass of copper sulfate in solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (160 g × 15%): 100% = 24g.

Let’s find the amount of aminoacetic acid substance by the formula:

n = m: M.

M (CuSO4) = 64 + 32 + 64 = 160 g / mol.

n = 24 g: 160 g / mol = 0.15 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

CuSO4 + 2NaOH = Cu (OH) 2 ↓ + Na2SO4.

According to the reaction equation, 1 mol of copper sulfate accounts for 1 mol of copper hydroxide. Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (CuSO4) = n (Cu (OH) 2) = 0.15 mol.

Find the mass of copper hydroxide by the formula:

m = n × M,

M (Cu (OH) 2) = 64 + 2 (16 + 1) = 98 g / mol.

m = 0.15 mol × 98 g / mol = 14.7 g.

Answer: 14.7 g.