Calculate the mass of the product obtained by hydrogenation of butene-2 weighing 168 g.
July 27, 2021 | education|
Let’s implement the solution:
Let’s compose the equation of the process:
m = 168 g X g -?
Н3С – СН = СН – СН3 + Н2 = СН3 – СН2 – СН2 – СН3 – hydrogenation, butane was formed;
Calculations according to the formulas of substances:
M (C4H8) = 56 g / mol;
M (C4H10) = 58 g / mol.
Let us determine the amount of butene – 2, if the mass is known:
Y (C4H8) = m / M = 168/56 = 3 mol;
Y (C4H10) = 3 mol since the number of these compounds is 1 mol.
Find the mass of the product:
m (C4H10) = Y * M = 3 * 58 = 174 g
Answer: the mass of butane is 174 g
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.