Calculate the mass of the product obtained by hydrogenation of butene-2 weighing 168 g.

Let’s implement the solution:

Let’s compose the equation of the process:
m = 168 g X g -?

Н3С – СН = СН – СН3 + Н2 = СН3 – СН2 – СН2 – СН3 – hydrogenation, butane was formed;

Calculations according to the formulas of substances:
M (C4H8) = 56 g / mol;

M (C4H10) = 58 g / mol.

Let us determine the amount of butene – 2, if the mass is known:
Y (C4H8) = m / M = 168/56 = 3 mol;

Y (C4H10) = 3 mol since the number of these compounds is 1 mol.

Find the mass of the product:
m (C4H10) = Y * M = 3 * 58 = 174 g

Answer: the mass of butane is 174 g