Calculate the mass of the salt obtained by reacting 16 grams of copper (II) oxide with 200 grams of 20% nitric acid solution.

1. Let’s compose the equation of the chemical reaction:

CuO + 2HNO3 = Cu (NO3) 2 + H2O.

2. Find the chemical amount of copper oxide and nitric acid:

n (CuO) = m (CuO) / M (CuO) = 16 g / 80 g / mol = 0.2 mol.

m (HNO3) = m (solution) * ω (HNO3) / 100% = 200 g * 20% / 100% = 40 g.

n (HNO3) = m (HNO3) / M (HNO3) = 40 g / 63 g / mol = 0.634 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of copper nitrate:

! CuO is in short supply.

n (Cu (NO3) 2) = n (CuO) = 0.2 mol.

m (Cu (NO3) 2) = n (Cu (NO3) 2) * M (Cu (NO3) 2) = 0.2 mol * 188 g / mol = 37.6 g.

Answer: m (Cu (NO3) 2) = 37.6 g.