Calculate the volume and number of molecules that 96 g of oxygen takes.

The molar mass of oxygen is:

M O2 = 16 x 2 = 32 grams / mol;

Let’s determine the amount of substance in 96 grams of oxygen:

N O2 = 96/32 = 3 mol;

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

The oxygen volume will be:

V O2 = 3 x 22.4 = 67.2 liters;

One mole contains 6.022 x 10 ^ 23 molecules.

The number of oxygen molecules will be:

K O2 = 3 x 6.022 x 10 ^ 23 = 1.8066 x 10 ^ 24 molecules;



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