1. Let’s compose the reaction equation for obtaining carbon dioxide from calcium carbonate:
CaCO3 = CaO + CO2 ↑;
2.Calculate the chemical amount of carbonate:
n (CaCO3) = m (CaCO3): M (CaCO3);
M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;
n (CaCO3) = 500: 100 = 5 mol;
3. Determine the amount of carbon dioxide:
n (CO2) = n (CaCO3) = 5 mol;
4.Calculate the volume of carbon monoxide (IV):
V (CO2) = n (CO2) * Vm = 5 * 22.4 = 112 liters.
Answer: 112 l.
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