Calculate the volume (l) of carbon monoxide (IV) that can be obtained from 500 g of calcium carbonate

1. Let’s compose the reaction equation for obtaining carbon dioxide from calcium carbonate:

CaCO3 = CaO + CO2 ↑;

2.Calculate the chemical amount of carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

n (CaCO3) = 500: 100 = 5 mol;

3. Determine the amount of carbon dioxide:

n (CO2) = n (CaCO3) = 5 mol;

4.Calculate the volume of carbon monoxide (IV):

V (CO2) = n (CO2) * Vm = 5 * 22.4 = 112 liters.

Answer: 112 l.