# Calculate the volume of ammonia that can be obtained by heating a mixture containing

**Calculate the volume of ammonia that can be obtained by heating a mixture containing ammonium chloride weighing 10.7 tons and calcium hydroxide taken in excess.**

This reaction proceeds according to the following chemical reaction equation:

(NH4) 2SO4 + Ca (OH) 2 = 2NH3 + CaSO4 + 2H2O;

Determine the chemical amount of ammonium chloride. For this purpose, we divide its weight by its molar mass.

To do this, we divide the weight of the substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The amount of ammonium sulfate will be:

N (NH4) 2SO4 = 10,700,000/132 = 81,061 mol;

With the decomposition of such an amount of salt, it is possible to obtain 81,061 x 2 = 162,121 mol of ammonia.

Let’s calculate its volume. To this end, we multiply the amount of substance by the volume of one mole of gas, which is 22.4 liters.

V NH3 = 162 121 x 22.4 = 3 631 515 liters = 3 631 m3;