Calculate the volume of ammonia that will be released from 20 grams of ammonium chloride when an excess

Calculate the volume of ammonia that will be released from 20 grams of ammonium chloride when an excess of calcium hydroxide solution is added, if the yield of the reaction product is 98%.

This reaction proceeds according to the following chemical reaction equation:

2NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2; + 2H2O;

Find the chemical amount of ammonium chloride. For this purpose, we divide its weight by its molar mass.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

The weight of ammonium chloride will be:

N NH4 Cl = 20 / 53.5 = 0.374 mol;

With 0.374 mol of ammonium chloride, 0.374 / 2 = 0.187 mol of calcium hydroxide will react. This will synthesize 0.374 mol of ammonia.

Let’s define its volume.

To do this, multiply the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters)

V NH3 = 0.374 x 22.4 = 8.3776 liters;