Calculate the volume of CO2 that is produced when 160 g of glucose is oxidized.

Glucose oxidation reaction:
C6H12O6 + 6O2 = 6CO2 + 6H2O.
1) The molar mass of glucose is: 12 * 6 + 1 * 12 + 16 * 6 = 72 + 12 + 96 = 180.
2) The amount of glucose substance is: 160/180 = 0.89 mol.
3) According to the reaction equation, there are six molecules of carbon dioxide per mole of glucose. Thus, the amount of carbon dioxide substance is: 0.89 / 6 = 0.15 mol.
4) The volume of carbon dioxide is found by multiplying the amount of carbon dioxide by the molar volume: 0.15 * 22.4 = 3.36 liters – the answer.