Calculate the volume of hydrogen at standard conditions. which is formed by the interaction of 1.3 g

Calculate the volume of hydrogen at standard conditions. which is formed by the interaction of 1.3 g of zinc with a solution of hydrochloric acid.

Zinc is a divalent metal. It attaches 2 chlorine atoms. Therefore, a double amount of acid is needed to react with zinc:

Zn + 2HCl → ZnCl2 + H2;

To solve the problem, we first determine the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 1.3 / 65 = 0.02 mol;

The reaction will produce the same amount of hydrogen.

Let’s calculate its volume:

V H2 = 22.4 x 0.02 = 0.448 liters;