Calculate the volume of hydrogen obtained by reacting 1.5 mol of methanol with metallic sodium, taken in sufficient quantity.
1. We write down the equation of interaction of methanol with sodium:
2CH3OH + 2Na → 2CH3ONa + H2 ↑;
2. find the chemical amount of hydrogen:
n (H2) = n (CH3OH): 2 = 1.5: 2 = 0.75 mol;
3. Determine the volume of hydrogen produced:
V (H2) = n (H2) * Vm = 0.75 * 22.4 = 16.8 dm3.
Answer: 16.8 dm3.
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