Calculate the volume of hydrogen obtained by the interaction of 14.4 g of zinc containing

Calculate the volume of hydrogen obtained by the interaction of 14.4 g of zinc containing 10% admixtures with an excess of hydrochloric acid solution.

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 14.4 x 0.9 / 65 = 0.199 mol;

The same amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 0.199 mol;

V H2 = 0.199 x 22.4 = 4.458 liters;




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