# Calculate the volume of hydrogen obtained by the interaction of 14.4 g of zinc containing

**Calculate the volume of hydrogen obtained by the interaction of 14.4 g of zinc containing 10% admixtures with an excess of hydrochloric acid solution.**

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 14.4 x 0.9 / 65 = 0.199 mol;

The same amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 0.199 mol;

V H2 = 0.199 x 22.4 = 4.458 liters;