Calculate the volume of hydrogen released by the interaction of 40.5 g of aluminum with a sulfuric acid solution.

Let’s write the reaction equation:

2Al + 3H2SO4 = Al2 (SO) 4 + 3H2

Let’s find the amount of aluminum:

n (Al) = m (Al) / M (Al) = 40.5 g / 27 g / mol = 1.5 mol

Let’s find the amount of released hydrogen:

n (H2) = 1.5 * n (Al) = 1.5 * 1.5 mol = 2.25 mol

Let’s calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 2.25 mol * 22.4 L / mol = 50.4 L

Answer: the volume of hydrogen is 50.4 liters.




One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.

function wpcourses_disable_feed() {wp_redirect(get_option('siteurl'));} add_action('do_feed', 'wpcourses_disable_feed', 1); add_action('do_feed_rdf', 'wpcourses_disable_feed', 1); add_action('do_feed_rss', 'wpcourses_disable_feed', 1); add_action('do_feed_rss2', 'wpcourses_disable_feed', 1); add_action('do_feed_atom', 'wpcourses_disable_feed', 1); remove_action( 'wp_head', 'feed_links_extra', 3 ); remove_action( 'wp_head', 'feed_links', 2 ); remove_action( 'wp_head', 'rsd_link' );