Let’s write the reaction equation:
2Al + 3H2SO4 = Al2 (SO) 4 + 3H2
Let’s find the amount of aluminum:
n (Al) = m (Al) / M (Al) = 40.5 g / 27 g / mol = 1.5 mol
Let’s find the amount of released hydrogen:
n (H2) = 1.5 * n (Al) = 1.5 * 1.5 mol = 2.25 mol
Let’s calculate the volume of hydrogen:
V (H2) = n (H2) * Vm = 2.25 mol * 22.4 L / mol = 50.4 L
Answer: the volume of hydrogen is 50.4 liters.
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