Calculate the volume of hydrogen sulfide that will result from the interaction of 0.88 iron (II)

Calculate the volume of hydrogen sulfide that will result from the interaction of 0.88 iron (II) sulfide with sulfuric acid.

1. Let’s compose the equation of the chemical reaction:

FeS + H2SO4 = FeSO4 + H2S.

2. Find the chemical amount of iron sulfide:

n (FeS) = m (FeS) / M (FeS) = 0.88 g / 88 g / mol = 0.01 mol.

3. According to the reaction equation, we find the chemical amount of hydrogen sulfide, and then its volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (H2S) = n (FeS) = 0.01 mol.

V (H2S) = n (H2S) * Vm = 0.01 mol * 22.4 L / mol = 0.224 L.

Answer: V (H2S) = 0.224 l.