Calculate the volume of hydrogen sulfide that will result from the interaction of 0.88 iron (II)
July 25, 2021 | education|
Calculate the volume of hydrogen sulfide that will result from the interaction of 0.88 iron (II) sulfide with sulfuric acid.
1. Let’s compose the equation of the chemical reaction:
FeS + H2SO4 = FeSO4 + H2S.
2. Find the chemical amount of iron sulfide:
n (FeS) = m (FeS) / M (FeS) = 0.88 g / 88 g / mol = 0.01 mol.
3. According to the reaction equation, we find the chemical amount of hydrogen sulfide, and then its volume (Vm – molar volume, constant equal to 22.4 l / mol):
n (H2S) = n (FeS) = 0.01 mol.
V (H2S) = n (H2S) * Vm = 0.01 mol * 22.4 L / mol = 0.224 L.
Answer: V (H2S) = 0.224 l.
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