# Calculate the volume of hydrogen that is formed by the interaction of 1.5 mol

**Calculate the volume of hydrogen that is formed by the interaction of 1.5 mol of aluminum with hydrochloric acid. How much hydrogen chloride will be required for this reaction?**

Aluminum reacts violently with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

The amount of metallic aluminum is given N Al = 1.5 mol;

The amount of hydrogen chloride required is 1.5 x 3 = 4.5 mol;

The chemical amount of released hydrogen will be: 1.5 x 3/2 = 2.25 mol

Let’s calculate its volume.

To do this, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 2.25 x 22.4 = 50.4 liters;