Calculate the volume of hydrogen that is formed by the interaction of 5 g

Calculate the volume of hydrogen that is formed by the interaction of 5 g of technical magnesium, containing 28% of impurities, with a solution of sulfuric acid.

Metallic magnesium dissolves in sulfuric acid solution. The chemical reaction proceeds according to the following equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s find the chemical amount of magnesium.

To do this, we divide its weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 5 x (1 – 0.28) / 24 = 0.15 mol;

An equivalent amount of hydrogen gas will be synthesized.

Let’s calculate the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.15 x 22.4 = 3.36 liters;