Calculate the volume of hydrogen that will be released when 126 g of zinc react with sulfuric acid.

Calculate the volume of hydrogen that will be released when 126 g of zinc react with sulfuric acid. The result is zinc sulfate and hydrogen.

1. The interaction of zinc with sulfuric acid proceeds according to the equation:

Zn + H2SO4 = ZnSO4 + H2 ↑.

2. Let’s calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 126: 65 = 1.9385 mol.

3. Determine the amount of released hydrogen:

n (H2) = n (Zn) = 1.9385 mol.

4. Let’s calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 1.9385 * 22.4 = 43.42 liters.

Answer: 43.42 liters.