Calculate the volume of hydrogen that will be released when 126 g of zinc react with sulfuric acid. The result is zinc sulfate and hydrogen.
1. The interaction of zinc with sulfuric acid proceeds according to the equation:
Zn + H2SO4 = ZnSO4 + H2 ↑.
2. Let’s calculate the chemical amount of zinc:
n (Zn) = m (Zn): M (Zn) = 126: 65 = 1.9385 mol.
3. Determine the amount of released hydrogen:
n (H2) = n (Zn) = 1.9385 mol.
4. Let’s calculate the volume of hydrogen:
V (H2) = n (H2) * Vm = 1.9385 * 22.4 = 43.42 liters.
Answer: 43.42 liters.
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