Calculate the volume of O2 required for complete oxidation of 12L ethene.

Let’s implement the solution:

According to the condition of the problem, we write the equation of the process:
С2Н4 + 3О2 = 2СО2 + 2Н2О + Q – combustion, heat, carbon dioxide, water is released;

Calculations by formulas:
M (C2H4) = 28 g / mol;

M (O2) = 32 g / mol.

Proportions:
1 mol of gas at normal level – 22.4 liters;

X mol (C2H4) – 12 liters from here, X mol (C2H4) = 1 * 12 / 22.4 = 0.5 mol.

0.5 mol (C2H4) – X mol (O2);

-1 mol -3 mol from here, X mol (O2) = 0.5 * 3/1 = 1.5 mol.

We find the volume of O2:
V (O2) = 1.5 * 22.4 = 33.6 L

Answer: the volume of oxygen is 33.6 liters



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.