Calculate the volume of oxygen required for the complete combustion of 5 liters of hydrogen sulfide.

Let’s implement the solution:
1. According to the condition of the problem, we write down the equation:
V = 5 liters. X l. -?
2H2S + 3O2 = 2SO2 + 2H2O – OBP, sulfur oxide is released (4);
2. Proportions:
1 mol of gas at normal level – 22.4 liters;
X mol (H2S) – 5 liters. hence, X mol (H2S) = 1 * 5 / 22.4 = 0.2 mol.
0.2 mol (H2S) – X mol (O2);
-2 mol -3 mol from here, X mol (O2) = 0.2 * 3/2 = 0.3 mol.
3. Find the volume of O2:
V (O2) = 0.3 * 22.4 = 6.72 liters.
Answer: The combustion process requires oxygen with a volume of 6.72 liters.