# Calculate the volume of oxygen required to obtain 60 liters of nitric oxide (II) from ammonia.

Calculate the volume of oxygen required to obtain 60 liters of nitric oxide (II) from ammonia. Gas volumes are measured under the same conditions.

1. Let’s compose the equation of the chemical reaction:

4NH3 + 5O2 = 4NO + 6H2O.

2. Find the chemical amount of nitric oxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (NO) = V (NO) / Vm = 60 L / 22.4 L / mol = 2.68 mol.

3. According to the reaction equation, we find the chemical amount of oxygen, and then its volume:

n (O2) = n (NO) / 4 * 5 = 2.68 mol / 4 * 5 = 3.35 mol.

V (O2) = n (O2) * Vm = 3.35 mol * 22.4 L / mol = 75 L.

Answer: V (O2) = 75 liters.

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