Calculate the volumes of oxygen and hydrogen that are produced by the decomposition of 90 g

Calculate the volumes of oxygen and hydrogen that are produced by the decomposition of 90 g of water with an electric current.

The water electrolysis reaction is described by the following chemical reaction equation:

2H2O = 2H2 + O2;

One mole of water produces one mole of hydrogen and half a mole of oxygen.

Let’s find the amount of a substance contained in 90 grams of water.

Its molar mass is 1 + 1 + 16 = 18 grams / mol;

N H2O = 90/18 = 11.25 mol;

1 mole of ideal gas under normal conditions takes a volume of 22.4 liters

The oxygen volume will be:

V O2 = 11.25 / 2 x 22.4 = 126 liters;

The volume of hydrogen will be:

V O2 = 11.25 x 22.4 = 252 liters;