Calculate the volumes of oxygen and hydrogen that are produced by the decomposition of 90 g of water with an electric current.
The water electrolysis reaction is described by the following chemical reaction equation:
2H2O = 2H2 + O2;
One mole of water produces one mole of hydrogen and half a mole of oxygen.
Let’s find the amount of a substance contained in 90 grams of water.
Its molar mass is 1 + 1 + 16 = 18 grams / mol;
N H2O = 90/18 = 11.25 mol;
1 mole of ideal gas under normal conditions takes a volume of 22.4 liters
The oxygen volume will be:
V O2 = 11.25 / 2 x 22.4 = 126 liters;
The volume of hydrogen will be:
V O2 = 11.25 x 22.4 = 252 liters;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.