The work A performed by the force F to move the body at a distance S is found by the formula: A = F ∙ S. In the case of uniform ascent, the traction force will be equal to the gravity of the body: F = m ∙ g, where the coefficient g ≈ 9.8 N / kg … We get:
A = m ∙ g ∙ S.
Then the work spent on lifting a body with a mass of m = 20 t = 20,000 kg to a height of S = 120 cm = 1.2 m will be:
A = 20,000 kg ∙ 9.8 N / kg ∙ 1.2 m; A = 235200 J ≈ 0.24 MJ.
Answer: the work is equal to ≈ 0.24 MJ.
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