Calculate what volume, under normal conditions, is occupied by a mixture of gases consisting of 0.3 mol H2, 0.4 mol N2 and 0.3 mol CO2.
Under normal conditions, all gases by nature and composition occupy the same volume, called molar – Vm = 22.4 l / mol. The volume of any gas in this case: V (g) = Vm * n (g).
Then the volume of gases:
V (total) = V (H2) + V (N2) + V (CO2) = Vm * n (H2) + Vm * n (N2) + Vm * n (CO2), where:
V (H2), n (H2) – volume and amount of hydrogen substance, respectively;
V (N2), n (N2) – volume and amount of nitrogen substance, respectively;
V (CO2), n (CO2) – volume and amount of carbon dioxide substance, respectively.
Let’s take Vm out of brackets: V (total) = Vm * (n (H2) + n (N2) + n (CO2)) = 22.4 * (0.3 + 0.4 +0.3)
V (total) = 22.4 l
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