Carbon dioxide obtained by the action of an excess of hydrochloric acid on 200 g of calcium carbonate is passed through

Carbon dioxide obtained by the action of an excess of hydrochloric acid on 200 g of calcium carbonate is passed through a solution containing 60 g of sodium hydroxide. determine the composition and mass of the resulting salt.

1. We write down the equation of the reaction of hydrochloric acid and calcium carbonate:

2HCl + CaCO3 = CaCl2 + H2O + CO2;

2.Calculate the chemical amount of calcium carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

n (CaCO3) = 200: 100 = 2 mol;

3. find the chemical amount of carbon dioxide:

n (CO2) = n (CaCO3) = 2 mol,

4.Calculate the chemical amount of sodium hydroxide:

n (NaOH) = m (NaOH): M (NaOH);

M (NaOH) = 23 + 16 + 1 = 40 g / mol;

n (NaOH) = 60: 40 = 1.5 mol

5.from the calculations of chemical quantities, it can be seen that sodium hydroxide is in short supply, therefore, as a result of the reaction, an acidic salt will be formed – sodium bicarbonate:

NaOH + CO2 = NaHCO3;

6. find the mass of bicarbonate:

n (NaHCO3) = n (NaOH) = 1.5 mol;

m (NaHCO3) = n (NaHCO3) * M (NaHCO3);

M (NaHCO3) = 23 + 1 + 12 + 3 * 16 = 84 g / mol;

m (NaHCO3) = 1.5 * 84 = 126 g.

Answer: 126 g NaHCO3.