Carry out the transformations: Al – Al2O3 – AlCl3 – Al (OH) 3 – NaAlO2. Give the reaction equations in molecular and ionic form.
Al → Al2O3 → AlCl3 → Al(OH) 3 → NaAlO2.
4Al + 3O2 = 2Al2O3
Al2O3 + 6HCl = 2AlCl3 + 3H2O
Al2O3 + 6H1+ + 6Cl1- = 2Al3++ 6Cl1- + 3H2O
Al2O3 + 6H1+ = 2Al3++ 3H2O
AlCl3 + 3NaOH = Al(OH)3 ↓+ 3NaCl
Al3+ + 3Cl1- + 3Na1+ + 3OH1- = Al(OH)3 ↓+ 3Na 1++ 3Cl1- .
Al3+ + 3OH1- = Al(OH)3 ↓ .
Al(OH)3 + NaOH = NaAlO2 + 2H2O.
Al(OH)3 + Na1+ + OH1- = Na1+ + AlO21- + 2H2O.
Al(OH)3 + OH1- = Na1+ + AlO21- + 2H2O.
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