# Compare the forces of gravity that act on 2 balls of the same volume р1 = 4 g / cm3 р2 = 6 g / cm3.

Given:

ro1 = 4 g / cm3 (gram per cubic centimeter) is the density of the first ball;

ro2 = 6 g / cm3 is the density of the second ball;

V1 = V2 = V – the volumes of the balls are the same.

It is required to compare F2 / F1 – the forces of gravity acting on the balls.

Let’s convert the units of measurement of density to the SI system:

ro1 = 4 g / cm3 = 4 * 10 ^ 3 = 4000 kg / m3 (kilogram per cubic meter);

ro2 = 6 g / cm3 = 6 * 10 ^ 3 = 6000 kg / m3 (kilogram per cubic meter).

Then:

F2 / F1 = m2 * g / (m1 * g), where m2, m1 are the masses of the balls, g is the acceleration of gravity;

F2 / F1 = ro2 * V2 * g / (ro1 * V1 * g) = ro2 * V2 / (ro1 * V1) = ro2 * V / (ro1 * V) =

= ro2 / ro1 = 6000/4000 = 6/4 = 1.5, or F2 = 1.5 * F1.

Answer: the second ball (with a higher density) is affected by gravity, one and a half times greater than the first ball.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.