Copper (ii) chloride and sodium hydroxide form an ionic and molecular equation.
| September 27, 2021 | education
The reaction takes place in two stages. Stage 1:
CuCl2 + 2NaOH = Cu (OH) 2 + 2NaCl
Cu2 + + 2OH- + 2Cl- + 2Na + = Cu (OH) 2 + 2Cl- + 2Na +
Cu2 + + 2OH- = Cu (OH) 2
Stage 2 (occurs only with an excess of alkali):
Cu (OH) 2 + 2NaOH = Na2 [Cu (OH) 4]
Cu (OH) 2 + 2OH- + 2Na + = 2Na + + [Cu (OH) 4] 2-
Cu (OH) 2 + 2OH- = [Cu (OH) 4] 2-
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