Copper oxide 2 weighing 32.0 g reacted with an excess of hydrochloric acid. determine:

| December 30, 2020 | education

Copper oxide 2 weighing 32.0 g reacted with an excess of hydrochloric acid. determine: a) the number of substances, reacted hydrogen chloride HCl b) the mass of the formed salt c) the mass of the formed water

Reaction: CuO + 2HCl = CuCl2 + H2O
The amount of oxide substance n = m / M = 32 g / 79.5 g / mol = 0.4 mol.
According to the reaction with 1 mol of oxide, 2 mol of HCl reacts, then 0.4 / 1 = n (HCl) / 2. The amount of the substance of the reacted HCl: n (HCl) = 0.4 * 2 = 0.8 mol.
According to the reaction, from 1 mol of oxide, 1 mol of salt is obtained, which means n (CuO) = n (CuCl2) = 0.4 mol. Salt mass m = n * M = 0.4 mol * 135 g / mol = 54 g.
From 1 mole of oxide, 1 mole of water is formed, n (H2O) = 0.4 mole. Water mass m = 0.4 mol * 18 g / mol = 7.2 g.



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