Initial data: k (spring rate) = 50 N / m; F (the force with which the spring acts) = 1 N.
We express the absolute elongation of the spring from the formula (Hooke’s law is used): F = Fcont. = k * Δl, whence Δl = F / k.
Let’s calculate: Δl = 1/50 = 0.02 m or 2 cm.
Answer: The absolute elongation of the spring was 2 centimeters.
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