Determine the absolute elongation of the spring with a stiffness of 50 N / m if it is acted on with a force of 1 N.

univerkov | September 27, 2021 | education

Initial data: k (spring rate) = 50 N / m; F (the force with which the spring acts) = 1 N.

We express the absolute elongation of the spring from the formula (Hooke’s law is used): F = Fcont. = k * Δl, whence Δl = F / k.

Let’s calculate: Δl = 1/50 = 0.02 m or 2 cm.

Answer: The absolute elongation of the spring was 2 centimeters.

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