Determine the acceleration of gravity on the surface of the planet Mars, if its mass is 64 * 10 ^ 22 kg, and the radius of the planet is 3400 km.
Given: Mm (mass of the planet Mars) = 64 * 10 ^ 22 kg; Rm (radius of Mars) = 3400 km (in SI Rm = 3400 * 10 ^ 3 m); G (gravitational constant) = 6.674 * 10 ^ -11 m3 / (s2 * kg).
The required acceleration of gravity on the surface of Mars is calculated by the formula: g = G * Mm / Rm ^ 2.
Let’s make a calculation: g = 6.674 * 10 ^ -11 * 64 * 10 ^ 22 / (3400 * 10 ^ 3) ^ 2 = 3.695 m / s2.
Answer: The acceleration of gravity on the surface of Mars, according to the calculation, is 3.695 m / s2.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.